-25x^2-50x+200=25x-10

Solution for -25x^2-50x+200=25x-10 equation:

-25x^2-50x+200=25x-10

We move all terms to the left:

-25x^2-50x+200-(25x-10)=0

We get rid of parentheses

-25x^2-50x-25x+10+200=0

We add all the numbers together, and all the variables

-25x^2-75x+210=0

a = -25; b = -75; c = +210;
Δ = b2-4ac
Δ = -752-4·(-25)·210
Δ = 26625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{26625}=\sqrt{25*1065}=\sqrt{25}*\sqrt{1065}=5\sqrt{1065}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-5\sqrt{1065}}{2*-25}=\frac{75-5\sqrt{1065}}{-50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+5\sqrt{1065}}{2*-25}=\frac{75+5\sqrt{1065}}{-50}
$